8-4[3(a+2)-2a]=0

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Solution for 8-4[3(a+2)-2a]=0 equation:


Simplifying
8 + -4[3(a + 2) + -2a] = 0

Reorder the terms:
8 + -4[3(2 + a) + -2a] = 0
8 + -4[(2 * 3 + a * 3) + -2a] = 0
8 + -4[(6 + 3a) + -2a] = 0

Combine like terms: 3a + -2a = 1a
8 + -4[6 + 1a] = 0
8 + [6 * -4 + 1a * -4] = 0
8 + [-24 + -4a] = 0

Combine like terms: 8 + -24 = -16
-16 + -4a = 0

Solving
-16 + -4a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -4a = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -4a = 0 + 16
-4a = 0 + 16

Combine like terms: 0 + 16 = 16
-4a = 16

Divide each side by '-4'.
a = -4

Simplifying
a = -4

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